Question

dividing radicals helpppppp

square root of 5 divided by 5 + square root of 2

2 - square root of 3divided by

Answer 1

\[\sqrt{5}\div5+\sqrt{2}\]

Answer 2

\[2-\sqrt{3}\div-2-\sqrt{5}\]

Answer 3

that would give you 1.861427128....

Answer 4

but how did u get that

Answer 5

the first one..gave you that

Answer 6

I have a texas ti-84 plues

Answer 7

i mean step by step

Answer 8

yea so do i

Answer 9

put it in you cal.

Answer 10

to put in the first
problem

Answer 11

i know but i need to show the work

Answer 12

Oh

Answer 13

so in you cal. do square root of 5

Answer 14

i need to show the work on papaer

Answer 15

I dont know how to show it on paper...

Answer 16

ur teacher must be trippin

Answer 17

thnkss anyway

Answer 18

i guess

Answer 19

\[\sqrt{5}\over5+\sqrt{2}\]

Answer 20

Step 1 multiply both the numerator by the conjugate of the denominator. In this problem the conjugate is:\[5-\sqrt{2}\] so your problem would now look like this:\[\sqrt{5}(5-\sqrt{2})\over(5+\sqrt{2}) (5-\sqrt{2}\] do you follow so far?

Answer 21

yess i do

Answer 22

r u there

Answer 23

Our fraction now becomes:\[5\sqrt{5}-\sqrt{10}\over25-2\] or\[\sqrt{5}(5-\sqrt{2})\over23\]\[2.236(5-1.414)\over23\]\[(2.236)(3.585)\over23\]\[8.01606\over23\]
.3485

Answer 24

thnk u theres another problem

Answer 25

You could, rather than rationalize the denominator just use your calculator. Lets do that on the second one.

Answer 26

ok thnks

Answer 27

\[2-\sqrt{3}\over-2-\sqrt{5}\]
\[2-1.732\over-2-2.236\]\[.268\over-4.236\]
-.06326

Answer 28

There is an error somewhere, the answer is negative, but larger negative than that!