Trigonometric limit question, see comment for equation.
\[\lim_{\theta \rightarrow 0}(2t)/(sint-t)\]
can we use calculus? L'hospital's rule?
I believe so.
L'hospital's rule once then evaluate got it?
I've been attempting to solve it and so far have only been able to factor out the "t" in the denominator, from there I am unable to figure out the next step.
do you know L'hospital's rule?
No, I don't believe I fully understand it. It doesn't look like anything that I have learned in class so far.
are you in calc or precalc?
calc
then you should use L'hospitals rule: when yuo have a limit that evaluates to 0/0 or infty/infty, take the derivative of the top and bottom, then see if you can take the limit again. That is L'hospital's rule. Want a demonstration for this problem?
or do you want to try it yourself?
Oh, ok I see now, we have been learning this just the name was unfamiliar. Right now it's the deriving that I'm getting stuck on so an example would be great.
I've got to go now, but you've been a great help. Thanks for clearing that up for me I appreciate it.
no time for the example? ok then good luck!
for future reference\[\lim_{t \rightarrow 0}\frac{2t}{\sin t-t}=\lim_{t \rightarrow 0}\frac{2}{\cos t-1}=-\infty\]
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