how is this even possible? solved in radians. when i work this with my calculator, 3y=-sin^-1 (2/11) , my result is -10.4757 . I also understand that these negative answers can be converted to positive values with reference to the unit circle. my question is, how do i convert my answer to concur with that of which is in the picture (below)

Question

sasogeek · Answer

attachment

sasogeek · Answer

Example 2 http://tutorial.math.lamar.edu/Classes/CalcI/TrigEquations_CalcII.aspx

mertsj · Answer

Perhaps your problem is that 3y=sin^-1(-2/11) not -sin^-2(2/11)

sasogeek · Answer

well i don't see how that is a wrong statement... sin(x)=1 => x = sin^-1 (1)    that's exactly what i did...

mertsj · Answer

3y=-sin^-1 (2/11)

mertsj · Answer

That's what you said you did.

sasogeek · Answer

-sin(x)=sin(-x)   so yeah that's what i did ... sin^-1(-2/11) and -sin^-1(2/11) should produce same results... right?

sasogeek · Answer

you can see that in the picture of what i wrote on the board... :| i think it's either i'm right and the solution on that page is wrong or I am just not doing something right...

mertsj · Answer

The solution on the page is right.

sasogeek · Answer

so where did i go wrong... i need the correct conversion to changing my negative answer to positive... probably that's the actual problem i should be dealing with

mertsj · Answer

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