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Mathematics 10 Online
OpenStudy (anonymous):

http://tutorial.math.lamar.edu/classes/calcII/IntegrationByParts_files/eq0020M.gif I wanna know how this has done Thanks

OpenStudy (anonymous):

no actually it ha to integration by parts

myininaya (myininaya):

Integration by parts! :) Let f=x and g'=e^(6x) => f'=1 g=e^(6x)/6

myininaya (myininaya):

\[\int\limits_{}^{}fg' dx=fg-\int\limits_{}^{}f'gdx\]

myininaya (myininaya):

plug it in! :)

OpenStudy (anonymous):

i got the answer but I don't know how it has done

OpenStudy (anonymous):

OpenStudy (anonymous):

I don't know how to do the last part of this problem

myininaya (myininaya):

\[x \cdot \frac{e^{6x}}{6}-\int\limits_{}^{}1 \cdot \frac{e^{6x}}{6} dx\] so do you understand this part?

myininaya (myininaya):

all i did was plug in

OpenStudy (anonymous):

yeah i did but i don't know how they got 11 and 7

myininaya (myininaya):

\[\frac{xe^{6x}}{6}-\frac{1}{6}\int\limits_{}^{}e^{6x} dx=\frac{xe^{6x}}{6}-\frac{1}{6} \cdot \frac{1}{6} e^{6x}+C\]

myininaya (myininaya):

so you are actually find with the integrating then you are having trouble plugin and the limits and simplifying?

myininaya (myininaya):

fine not find

OpenStudy (anonymous):

i got same your answer but I have different answer in this site

myininaya (myininaya):

\[\int\limits_{-1}^{2}xe^{6x} dx=[\frac{xe^{6x}}{6}-\frac{1}{36}e^{6x}]_{-1}^{2}\]

myininaya (myininaya):

\[=[\frac{2e^{6(2)}}{6}-\frac{e^{6(2)}}{36}]-[\frac{-1e^{6(-1)}}{6}-\frac{e^{6(-1)}}{36}]\]

myininaya (myininaya):

\[=\frac{1e^{12}}{3}-\frac{e^{12}}{36}+\frac{e^{-6}}{6}+\frac{e^{-6}}{36}\]

myininaya (myininaya):

\[=\frac{12-1}{36}e^{12}+\frac{6+36}{36}e^{-6} \] \[=\frac{11}{36}e^{12}+\frac{42}{36}e^{-6}=\frac{11}{36}e^{12}+\frac{7}{6}e^{-6}\]

OpenStudy (anonymous):

OpenStudy (anonymous):

Thank you very much Myininaya Can you see the answer ?

myininaya (myininaya):

oh i see where i made a mistake

myininaya (myininaya):

do you see my mistake?

myininaya (myininaya):

so we have this \[=[\frac{2e^{6(2)}}{6}-\frac{e^{6(2)}}{36}]-[\frac{-1e^{6(-1)}}{6}-\frac{e^{6(-1)}}{36}] \]

myininaya (myininaya):

\[=\frac{12-1}{36}e^{12}-\frac{-6-1}{36}e^{-6}\]

myininaya (myininaya):

there we go

myininaya (myininaya):

lol i wrote 1/36 as 36/36 above thats why it came out wrong the first try

OpenStudy (anonymous):

yeah that make sense but how did you get 12

myininaya (myininaya):

common denomaintor?

myininaya (myininaya):

\[\frac{2}{6} \cdot \frac{6}{6}=\frac{12}{36}\]

OpenStudy (anonymous):

yeah that make sense to me You help me a lot I really thank you so much that was very helpful to me

myininaya (myininaya):

np

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