graphical problem: The hypotenuse of right angled triangle has end points (1,3) and (-4,1). find the equation of the perpendicular sides(other two sides) of the triangle?
There are an infinite number of solutions to this question unless more information is given. A simple proposition in geometry states that if we consider the hypotenuse of a triangle as the diameter of a circle, then any triangle with its third vertex on the circle will be a right triangle. Notably, this means that we can pick the third vertex to be any other point (other than the two given, as this would form a degenerate triangle, aka a line segment) on the circle. Since the choice of the third vertex would determine the "equations" of the other two sides, there is no unique answer without more information.
use the equations of strait lines.
I assumed that's what you meant, but what I said still stands, there is not a unique solution to your problem. Consider the following drawing, where the hypotenuse is the diameter of the circle. Since any third point on the circle gives you a right triangle, there is no single solution to your problem. To convince yourself of this, choose any of the squares I placed on the circle. Note that each of these squares, if taken as the third vertex of the triangle will form a right triangle, and clearly all of these will have different equations for their sides. |dw:1326536772254:dw|
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