A sphere of mass m1 and a block of mass m2 are connected by a light cord that passes over a pulley, as shown in the opposite Figure. The radius of the pulley is R, and the mass of the rim is M. The spokes of the pulley have negligible mass. The block slides on a frictionless, horizontal surface. Find an expression for the linear acceleration of the two objects, using the concepts of angular momentum and torque .....in this problem :1-does the tension in the two strings have a torque?why are torques ignored
2-what it is the angular momentum of m1,m2 ?the position vector for these masses is...?

Question

A sphere of mass m1 and a block of mass m2 are connected by a light cord that passes over a pulley, as shown in the opposite Figure. The radius of the pulley is R, and the mass of the rim is M. The spokes of the pulley have negligible mass. The block slides on a frictionless, horizontal surface. Find an expression for the linear acceleration of the two objects, using the concepts of angular momentum and torque .....in  this problem :1-does the tension in the two strings have a torque?why are torques ignored
2-what it is the angular momentum of m1,m2 ?the position vector for these masses is...?

sriram · Answer

figure please

anonymous · Answer

attachment

anonymous · Answer

the figure is attached to the previous reply

sriram · Answer

assume the sphere goes down by x
it is now havin vel v
conserve energy
m1gx=1/2 *m1*v^2  +  1/2*m2*v^2 +1/2*M*R^2/2*w^2
w=v/R
m1gx=v^2/2[m1+m2+M/2]
we get vel in terms of displacement

anonymous · Answer

(m.o.i of m1)I*g-t=m2*a
I DONT THINK WE DO MOMENTUM CONSERVATION HERE
there is no torque as the sphere does not rotate in order to rotate the string