Question

form the DE of family of circles touching y-axis at origin .

Answer 1

\[x^2+y^2=2ax \] After D. w.r.t.x \[2x+2yy'=2a\]

Answer 2

Now if i Differentiate it again im getting a different answer

Answer 3

different answre from?

Answer 4

I have the solution

Answer 5

Can you do this problem ?

Answer 6

I am trying to understand what it's asking to do

Answer 7

okay

Answer 8

\[x^2+y^2=2ax\]

was ^ this given or you came up with it?

Answer 9

I came up with it

Answer 10

circle

\[x^2+y^2=a^2\]
we need to move it to right by a/2

\[(x-a/2)^2+y^2=a^2\]

\[x^2-ax+a^2/4+y^2=a^2\]

Answer 11

diff -->

\[2x-a+2y y'=0\]

Answer 12

2x+2y y'= a

Answer 13

now ?

Answer 14

ill do it in diff eqn

Answer 15

ok :)

Answer 16

2y y' =-2x +a

y'= -x/y + a/2y

y'= (-2x+a)/2y

Answer 17

Given Answer is 2xyy' + x^2 = y^2