Find the slope and y-intercept of the line 4x + 5y − 1 = 0
If you write it in the form y = mx + b, m = slope and b = y-intercept
basically solve the equation for y: \[y = -\frac{4}{5}x + \frac{1}{5}\] now you can tell what m and b are....what are they?
m=-4/5 b=1/5
yes!
whats my y intercept?
y intercept is the number which is floating around once you have the equation in the form y=mx + b. It is b. Which means in our example the y-intercept is 1/5
and my x would be?
x is allowed to vary across the interval on which the line is defined, which is usually the entire number line.
your gradient is m, and in this case it is -4/5.
do you see that as x varies y varies too?
ok. im confused how i would graph the x,y intercept
put a pencil dot on the y-axis at 1/5. Count -4 units down on the y axis, then count 5 units to the right and then put a pencil dot there. Connect the two dots and that is your line.
yes that picture is good. So you start at 1/5 on the y-axis and make a mark. Then do 1/5 - 4 = -19/5. Then at -19/5 on the y-axis you count out 5 units to the right and make a mark. Those two marks are joined to make your line.
ugh! my x would be 5 or 4?
x has no value unless you give y a value...and conversely.
ok. still not getting it. thNKS
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