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Mathematics 14 Online
OpenStudy (anonymous):

limit x/1-cosx x-->0

OpenStudy (anonymous):

use L'Hopital's Rule on x/(1-cos(x))

OpenStudy (anonymous):

L'Hopital's Rule cant work here.. it will male it1/0 form...

OpenStudy (anonymous):

so what will the answer be?

OpenStudy (anonymous):

m trying , lets see

OpenStudy (anonymous):

lim x/2sin^2(x) = (x^2/4)/(2x sin^2(x/2) = lim 1/(2x) =infinite x-->0 x-->0 i think so...but not 100% sure...

OpenStudy (anonymous):

L'Hopital works by not working - after all the answer is +infinite or -infinite depending on whether you come from 0+ or 0- ... take a look at the graph of x/(1-cos(x)) at 0 for example by typing lim_(x->0) x/(1-cos(x)) into WolframAlpha at www.wolframalpha.com: http://www.wolframalpha.com/input/?i=lim_%28x-%3E0%29+x%2F%281-cos%28x%29%29

OpenStudy (anonymous):

good job

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