Every nonzero vector space V contains a nonzero proper subspace true false
please explain your ans
false
how false
look at the vector space that has the basis vector \{(1,0)\} so V=span( \{(1,0)\}) the only proper subspace of V is the zero subspace
\[V=\text{span}(\{(1,0)\})\]
do you see why?
plz explain if u can ''the only proper subspace of V is the zero subspace''
Suppose W is a proper subspace of V and that W is not the zero subspace....
then there is a nonzero vector \(w\in W\)
the vector \(w\) has the form (x,0) where \(x\ne 0\) then \[(x,0)/x=(1,0)\in W\] thus W=V ...a contradiction
what is proper subspace? is it like proper subset
sort of
W is a proper subspace of V if W is a vector space and every vector in W is in V, but W\(ne\)V
W\(\ne\)V
means proper subspace is actually a proper subset in which properties of vector space is satistied right?
yes
ok thanks a lot
np
@zarkon please help if u can. Similar matrices represent the same linear transformation. please prove it or send me a link of its prove its urgent....
look at http://mathprelims.wordpress.com/2009/06/25/definition-of-similarity-using-linear-transformations/
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