Question

please help me solve this equation using trigonometric integrals. ʃcsc^6xdx

Answer 1

w8

Answer 2

This may be of assistance -> http://en.wikipedia.org/wiki/Integration_by_reduction_formulae

Answer 3

\[\int sin^{-6}(x)dx\]

Answer 4

\[\int\limits_{?}^{?}i-\cos^3(2x)\]

Answer 5

sorry not i , its 1

Answer 6

its easier now

Answer 7

integral of 1 is x, so now we only have to integrate cos^3(2x)

Answer 8

now we can apply reduction formula

Answer 9

answer is \[x+\sin2xcos^2(2x)+4\sin2x\]

Answer 10

how did ʃcsc^6xdx become ʃcos^3(2x)?

Answer 11

it became 1+cos^3(2x)

Answer 12

by applying identity i did a minor mistake it shud b 1/2+1/2cos^3(2x)

Answer 13

by applying identity cos2x=1-2sin^2x

Answer 14

then i applied reduction formula to cos^3(2x)

Answer 15

thank you :)

Answer 16

u can check the reduction formula fsm jus posted above

Answer 17

okay C: