- so if we need to prove that every primes grater than 2 can be writing in the form of 2n+1 - how is possible do it this proof ?
well, proving is quite perspiring job mentally..
in mathematics this not working acceptably never
Suppose that p is prime and that p > 2. Then if \[p \neq 2n + 1\] for some n, then p must be even. Hence it can be written in the form p=2n for some n. However p is prime by assumption, and cannot be divided by anything but itself and 1. 2n can be divided by 2 which is a contradiction. Hence p is of the form p=2n+1 for some n. Lol I'm not convinced by this but it's been a long time since i've seen any arguments like this...
callum29, could you help my problem??
please??
,,Callum29" - thank you - so this is right sure and understandably easy but in mathematics every statement is acceptably when this was proven that is true ... - so can you do it , can you prove it ?
now I don't understand your question...
can you help me with this callum29?? please? x=2(mod 3) x=3(mod 7) x=7(mod 5) find a unique incongruent solution to modulo n. (number theory problem using chinese remainder theorem) please help!!
,,Callum29" can you prove it that every primes grater than 2,can be writing in the form of 2n+1 ?
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