I need help in finding the values of A,B and C in this identity. thanks!
\[2x^{4} - 13x^{3}+19x ^{2}+5x+1=(x-4)(Ax+1)(x ^{2}+Bx+1)+C\]
I know the first step is to substitue x=4 and i will find C=5. but i don't know how to continue from here.. help please :)
a=2,b=-3,c=5
sorry, but could you tell me how did you get a and b? :/
once you get the value of c then subtract it from the original expression and divide it with x-4 and then you get a cubic expression in it compare the coefficients of different powers of x so as to get the values of A an dB
hey but i thought we have to keep substituting the value of x to get A and eventually B?
it is easier to compare than to substitute for here you will have to employ substitution of variables
do you want steps?
Okay sure :)
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