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help me with this integral
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\[\int\limits_{0}^{1}dy \int\limits_{y}^{1}\sin(x ^{2})dx\]
@meverette once you are done with this question, I would appreciate if you please take a look at http://openstudy.com/users/2bornot2b#/updates/4f128c87e4b0a4c24f584fa3
If you change the order of integration, you're left with an extra x term to allow the u-substitution u=x^2. Try: \[\int\limits_{0}^{1} (\int\limits_{0}^{x} \sin(x^2)dy) dx\]
I get \[1/2-1/2*\cos1\] but i dot know if this is right or not...but thank you very much
looks right. also I typed "integral_0^1 integral_y^1 sin(x^2)dxdy - (1/2 - cos(1)/2)" into WolframAlpha.com and (eventually) got 0.
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