Find the inverse of the Matrix using elementary transformation
\[\begin{bmatrix} 2 & 0 &-1 \\ 5& 1 &0 \\ 0 & 1& 3 \end{bmatrix}\]
its a long process... :)
is there any easy way ? because i usually end up with wrong answers (actually i dont get the right answer )
did you try the method imran posted?
Minors & cofactors ?
yeah that one
yea ...its also same long method... :)
But i cant use it here
are you supposed to do this \[\begin{bmatrix} 2 & 0 &-1 \\ 5& 1 &0 \\ 0 & 1& 3 \end{bmatrix}\times \begin{bmatrix} a_{11} & a_{12} &a_{13} \\ a_{21}& a_{22} &a_{23}\\ a_{31} & a_{32}& a_{33} \end{bmatrix}=\begin{bmatrix} 1 & 0 & 0\\ 0& 1 &0 \\ 0 & 0& 1 \end{bmatrix}\]
Yes
oh man i remember this. it is a real pain. you write one your matrix next to the identity, and then keep track as you go to make turn your matrix in to the identity. a decent explanation is here, but it takes for flippin ever http://www.purplemath.com/modules/mtrxinvr.htm
Lol the thing is i hardly get the right answer I'll check it out Thankyou Satellite :)
Here's a rather thorough list of ways to find inverse matrices. I like the one sat mentioned, illustrated in examples 1, 2, and 3 in the link: http://tutorial.math.lamar.edu/Classes/LinAlg/FindingInverseMatrices.aspx
OK thankyou :) i'll check it out !! :)
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