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How do I differentiate this function?
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f(x)= \[4^{3x}\]
\[\frac{d}{dx}b^x=b^x\ln(b)\]
you will need the chain rule here because you have \[4^{3x}\] so don't forget to multiply by 3
if you need a method, you could do one of two things. rewrite \[4^{3x}=e^{3x\ln(4)}\] and take the derivative of that
or take the log, get \[\ln(4^{3x})=3x\ln(4)\] take the derivative and then multiply by the original function. but it is easiest just to remember how to differentiate \[b^x\]
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