Question

solve log(base 27)x=1-log(base 27) (x-0.4)

Answer 1

hint:\[27^{1-\log_{27}(x-0.4)}=\frac{27}{x-0.4}\]

Answer 2

can you show full solution please

Answer 3

No, but I can guide you through it.
I have shown you the right side, what will you get by raising 27 to the power of the left side?

Answer 4

\[\log_{27}x=1-\log_{27}(x-0.4)\]\[27^{\log_{27}x}=27^{1-\log_{27}(x-0.4)}\]\[x=\frac{27}{x-0.4}\]you can take it from here I hope