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OpenStudy (anonymous):

At 142◦C, the pressure of a sample of nitrogen is 1.92 atm. What will the pressure be at 218◦C, assuming constant volume? Answer in units of atm

OpenStudy (anonymous):

please help ):

OpenStudy (anonymous):

Use ideal gas law, which says:\[\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\]Where P-pressure; V-volume, T-temperature Since V1=V2, you can simplify this expression to:\[\frac{P_1}{T_1}=\frac{P_2}{T_2}\] So, first convert temperatures from Celsius to Kelvin \[\ T_1= 142 + 273.15 = 415.15 K\]\[\ T_2= 218 + 273.15 = 491.15 K\]\[\ P_1= 1.92\ atm\] Solve the above expression for P2 and plug in the values.

OpenStudy (anonymous):

so it's 391489.7712

OpenStudy (anonymous):

Well, no. You can tell that this is wrong just by looking at the number you got, that's a pretty big pressure :D.What expression did you get for P2?

OpenStudy (anonymous):

|dw:1326667475440:dw|

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