At 142◦C, the pressure of a sample of nitrogen is 1.92 atm. What will the pressure be at 218◦C, assuming constant volume? Answer in units of atm
please help ):
Use ideal gas law, which says:\[\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\]Where P-pressure; V-volume, T-temperature Since V1=V2, you can simplify this expression to:\[\frac{P_1}{T_1}=\frac{P_2}{T_2}\] So, first convert temperatures from Celsius to Kelvin \[\ T_1= 142 + 273.15 = 415.15 K\]\[\ T_2= 218 + 273.15 = 491.15 K\]\[\ P_1= 1.92\ atm\] Solve the above expression for P2 and plug in the values.
so it's 391489.7712
Well, no. You can tell that this is wrong just by looking at the number you got, that's a pretty big pressure :D.What expression did you get for P2?
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