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How do I solve this quadratic equation by factoring: 2x^2 - 3x = 0
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You need to take out the common factor in both terms. Can you see what it is?
Isn't it product 2 and sum: -3?
okay we have 2x^2 - 3x = 0 There is a x in the 3x term and a x in the 2x^2 term. THis is all we can take out.
okay.
\[2x^2-3x=0\]\[x(2x-3)=0\] So x=0 Or 2x-3=0 2x=3 x=3/2
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ohhh.. so it's not like (2x^2 -2) + (-3x +1)...? thank you!!
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