Question

If y=Arcsin(3x/4), then dy/dx is

Answer 1

i will let him do it the easy way lol

Answer 2

\[\frac{d}{dx}\arcsin(x)=\frac{1}{\sqrt{1-x^2}}\] there i said it!

Answer 3

\[\frac{d}{dx}\arcsin(u)=\frac{u'}{\sqrt{1-u^2}}\]

Answer 4

so you only need to replace u by
\[\frac{3x}{4}\] and
\[u'\] by
\[\frac{3}{4}\]

Answer 5

So would I come out with [3/\sqrt{16-9x^2}\]