Anyone good at work problems?
- I have few questions to ask :)
?
Just type your questions here and people will try and answer them.
Yup I will right now
A pump can fill a tank in 6 hours. Another pump can fill the same tank in 3 hours. How much time will it take to fill the tank if both pumps work together?
1.5 hours
& how did you get that? please i'm not here for answers! I have an exam tmrw & I need to know how to do them :)
dhash i guess its wrong
how much is filled in one hour by both pumps?
answer is 2 hour
1/6 filled + 1/3 filled = how much filled in an hour?
1st pipe DATA: time = 6 hr/job ; rate = 1/6 job/hr 2nd pipe DATA: time = 3 hr/job ; rate = 1/3 job/hr Together DATA: time = x hr/job ; rate = 1/x job/hr 1/x=1/3+1/6=3/6=1/2 =>x=2 so it will take 2 hours
1/6+2/6= 3/6 = 1/2 ?
ya
2 hours is the right answer.
the tank is half full after an hour, another hour makes it filled all the way
/- fraction
the key is to find out how much work is done in a single unit of time (hour, second, week, etc)
and extrapulate from that a full load
Why did you change it to 1/6 and 1/3 ?
suppose if the capacity of tank is 12 litres, and pump one fills the tank in 6 hour , it means filling rate is 2 litres per hour. And take second tank, if it fills in 3 hours, it means its filling rate is 4 litres per hour. Hence it means that if their filling capacity combine we will have a rate of 6 litres per hours. As the capacity is 12 litres, hence it wud b filled in 2 hour
if it takes 6 hours to fill; then in one hour, only 1/6 is filled
in order to consider the work
i think this explanation will do it
if it takes 3 hours to fill, then in one hour its only 1/3 full
1/6 full + 1/3 full = 1/2 full
& how did 1/2 came to 2 hours ?
how many halves make a whole?
1hour + 1hour = 2 hours 1/2 1/2 1
Aooo! Okay thank you :)
In other words work done is direct proportional to the time.
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