Question

what is the domain of the following (use interval notation) : f(x)= 1/(3x+5)

Answer 1

f(x)=1/(3x+5)
3x+5 can't be 0
i.e x cant be -5/3
so the domain is (-infinity, -5/3) U (-5/3, infinity) or Real-{-5/3}

Answer 2

Anything that doesn't make (3x+5) = 0.

Answer 3

also, how do I find the domain of \[f(x)=\sqrt{2x-7}\]

Answer 4

I'm going to assume you're only dealing in real numbers, so you can't take the square-root of a negative. So (2x - 7) >= 0. Can you work it out from there?

Answer 5

Swilly , inside the square root we should have a quantity greater than 0
2x-7>=0
2x>=7
x>=7

Answer 6

7/2

Answer 7

\[[3.5, \infty)\]

Answer 8

sorry it should be 7/2 or 3.5

Answer 9

ok thank you