The positions, p, of two objects, in metres, after t>= seconds are given by the following functions: p1(x)=xcosx+2 and p2=xsinx+1. When are the objects less than 2m apart during the first 20 secs?
well, that depends on x ... did you mean that p1(t) = tcost(t) + 2 and p2(t) = tsin(t) + 1 after t seconds?
sorry yeah x is t
If so, you want to find |p1(t)-p2(t)| < 2.00
ohh
oh so wud i have to use graphing technology to find that?
Not necessarily you can derive a crazy trig identity like: sin(x)-cos(x) = -sqrt(2) (sin (x - pi/4)
Assuming \[p1(t)=t \cos(t)+2\ and\ p2(t)=t \sin(x)+1\] Then |p1(t)-p2(t)| <2 has 7 intervals between 0 and 20 seconds. You can find them analytically, and preferably graphing first.
are your trig functions cosine and sine expecting Degrees or Radians?
radians
hmm lemme try this
thanks
thanks guys i got it!
You're welcome! :)
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