The positions, p, of two objects, in metres, after t>= seconds are given by the following functions: p1(x)=xcosx+2 and p2=xsinx+1. When are the objects less than 2m apart during the first 20 secs?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
well, that depends on x ... did you mean that p1(t) = tcost(t) + 2 and p2(t) = tsin(t) + 1 after t seconds?
OpenStudy (wondermath):
sorry yeah x is t
OpenStudy (anonymous):
If so, you want to find |p1(t)-p2(t)| < 2.00
OpenStudy (wondermath):
ohh
OpenStudy (wondermath):
oh so wud i have to use graphing technology to find that?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Not necessarily you can derive a crazy trig identity like: sin(x)-cos(x) = -sqrt(2) (sin (x - pi/4)
OpenStudy (mathmate):
Assuming
\[p1(t)=t \cos(t)+2\ and\ p2(t)=t \sin(x)+1\]
Then |p1(t)-p2(t)| <2 has 7 intervals between 0 and 20 seconds.
You can find them analytically, and preferably graphing first.
OpenStudy (anonymous):
are your trig functions cosine and sine expecting Degrees or Radians?
OpenStudy (wondermath):
radians
OpenStudy (wondermath):
hmm lemme try this
Still Need Help?
Join the QuestionCove community and study together with friends!