How many ml would it take to prepare 500 ml of a .10M nitric acid (HNO3) solution from a stock solution of nitric acid that is 69.0% pure and has a specific gravity of 1.42 g/ml?

Question

anonymous · Answer

you need 0.1 mole in 1litre
0.05 mole in 0.5 litre
69 gram in 1 kg
3.15 gram in (1kg)*(3.15/69)
3.15 gram in 50.7 g solution
3.15 g in 50.7/1.42 ml
3.15 g in 35.7ml
add 35.7 ml acid solution and increase volume upto 500ml