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Internal telephone numbers in a university are composed of 5 digits. The first two digits can form any integer between (and including) 61 and 75, the third digit is an integer between 1 and 9 and the last two each take any integer value. The total number of possible internal telephone numbers is....
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is it 15 times 9 times 100 = 13500
15 choices from 61 to 75, 9 choices 1-9 and the last two each take any integer value so that means 0 to 9 = 10 choices for both. 15 * 9 * 10 * 10 = 13500
thanks lauriy can you help me check the other stats problem if you have time :-)
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