The total number of ways one can arrange 5 math books, 3 physics books, and 2 statistics books on a bookshelf, if no 2 books of the same subject can be placed next to each other, is...
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OpenStudy (anonymous):
assume the books within each subject are distinct from each other
OpenStudy (anonymous):
hold on im looking at it
OpenStudy (anonymous):
10!
OpenStudy (anonymous):
5choose2 times 2factorial
OpenStudy (anonymous):
just 5 choose 2
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OpenStudy (anonymous):
k
OpenStudy (anonymous):
you still there 2be?
OpenStudy (anonymous):
alright will u be on for the next 5 mins or so
OpenStudy (anonymous):
k thanks
OpenStudy (anonymous):
what does 5 permute one mean in words
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OpenStudy (anonymous):
k im doing it by thinking of it as slots
OpenStudy (anonymous):
i get 1200 ways
OpenStudy (anonymous):
(5!*5!)/(3!*2!) = 1200
OpenStudy (phi):
Here's my shot at it
OpenStudy (phi):
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OpenStudy (anonymous):
ok this is my reasoning
OpenStudy (anonymous):
the only way such a arrangement can be possible is if all the math books are spaced out so there are 2 possible ways this can happen, that the 10 slots start with a math book or end with a math book giving us a total of 5! * 2
OpenStudy (anonymous):
then , the remaining 5 slots in between the math books can be taken by the 5 other books in any order
OpenStudy (anonymous):
so to correct myself its 5!*5!*2
OpenStudy (anonymous):
28800
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