Question

Differentiation and integration for
y=2cos 3x/e^{2x}

Answer 1

y'=(2.3(-sin3x).e^2x-2cos3x.2.e^2x)/(e^2x)^2
=(-6sin(3x)e^2x-4cos(3x)e^2x)/e^4x

Answer 2

-6e^(2x)*sin3x-4cos3x*e^(2x) all over e^(4x)

Answer 3

iono integrate it...

Answer 4

integration solution is long if you want,i will study write it.

Answer 5

No,thank you cnsu 90.

Answer 6

cos3x=u -3sin3xdx=du and e^-2x dx=dv v= -2e^2x I=uv-int_vdu then integrate 2 times