Question

Write the slope intercept form of a line passing through (-1,4) and (2,-2)

Answer 1

what do you get when you subtract one point from the other?

Answer 2

hard to have a conversation when they vanish; but it could be a bad connection ontheir end i spose

Answer 3

subtract your points and stack y/x for slope: m

then pick either point (Px,Py) and construct the equation:

y = mx -mPx + Py

Answer 4

The answer that I came up is y=3x+1. The teacher says its y=2x+2

Answer 5

(-1,4)
-( 2,-2)
------
-3,6; slope = y/x = 6/-3 = -2

y = -2x +2(-1)+4
= -2x -2+4
= -2x + 2

Answer 6

youre teachers is closest :)

Answer 7

im still unsure. going over your answer

Answer 8

isn't the formula y1-y2/x1-x2

Answer 9

we can test it out to BE sure:

y = -2x + 2 ; try out (-1,4)
4 -1
-----------
4 = 2 + 2 ; thats good


y = -2x + 2 ; try out (2,-2)
-2 2
----------
-2 = -4+2 thats good as well

Answer 10

the formula is just a compact way to write the steps, you still have to do the steps.

P(x1 , y1)
-Q(x2 , y2)
------------
(x1-x2, y1-y2); slope = y/x = (y1-y2)/(x1-x2)

but even that is misleading because it doesnt matter which point you start with

Answer 11

m=-2-4[\div-2-1\] and I came up with -6/2 =-3

Answer 12

your not keeping track of your numbers to well, which happems to me when i try this horizontal conflagerations.

I always do a vertical format so that i dont mix up numbers

Answer 13

if we do "the formula"

m = (4--2)/(-1-2) = 6/-3 = -2

or

m = (-2-4)/(2--1) = -6/3 = -2

Answer 14

ooohhh I see what i did. I didn't change my negative to a positive

Answer 15

:) good catch

Answer 16

oh ok I got it...thank you so much for your help

Answer 17

youre welcome :)