Question

Number 17

Answer 1

To solve this, you simply set y = 0, and solve for x. The right-most x will be a bigger value than the leftmost x

Answer 2

ok i got to x^2-6x+6 ...where do i got from here?

Answer 3

x^2 - 6x + 6 = 0

Answer 4

i plugged zero in for y, foiled on one side, and subtracted 3

Answer 5

Did you figure it out yet?

Answer 6

nope, just got the wrong answer

Answer 7

o wait, do i use the quadratic formula?

Answer 8

Try (4.732, 0)

Answer 9

its just 4.732 because its only asking for the x coordinate

Answer 10

I see

Answer 11

so how did u get that #?

Answer 12

I approximated \[x = \sqrt{3} + 3\]

Answer 13

how did u get that from x^2-6x+6=0?

Answer 14

Well, to be honest, I back tracked to when you had

3 = (x-3)^2

Instead of putting everything on one side, I simply square rooted both sides to get:

sqrt{3} = x - 3

Then I added 3 to both sides. Why? Because we wanted to solve for x.

Answer 15

Ok I see