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Pre-Calculas question, see comments for problem.
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Solve for "x" \[\log_{3}((x-1)^{2})-2\log_{3}(3x-1)=1 \] I am quite rusty on my log's, and am a little unsure of how to go about solving this.
start with \[\log_3(\frac{(x-1)^2}{(3x-1)^2})=1\] then write in equivalent exponential form
\[\left (\frac{x-1}{3x-1} \right) ^2=3\]
after that you are on your own, because that does not seem trivial to solve
well maybe. take the square root, then multiply out etc
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