Question

descartes rule of sigs to determine the possible number of positive and negative real zeros for each giving function.


f(x)= x^3 +2x^2 + 5x + 4

Answer 1

but in this one we dont have to use synthetic devision

Answer 2

but you need to know one soloution to use synthetic division

Answer 3

When I was in highschool, we would graph it in calculator then use it to find other solution using synthetic division

Answer 4

2X^4 -5x^3-x^2 - 6x+4 it has two sign changes and my teacher told me to divide it by and even number
so what next im stuck at 2 and 1

Answer 5

are you sure your function is right because solution are irrational

http://www.wolframalpha.com/input/?i=2%28x%29%5E4-5%28x%29%5E3-%28x%29%5E2-6%28x%29%2B4

Answer 6

thats what i have in my book
for sure
\[2X^4 -5x^3-x^2 - 6x+4\]

Answer 7

and what does it what you to do?

Answer 8

descartes rule of signs to determine the possible number of positive and negative real zeros for each giving function.

Answer 9

there are 2 sign changes in your function which mean , you have 2 solution or an even number lower -- O solution .

Answer 10

as my answer i wrote there are 2 solutions which are 2 and 1

Answer 11

2x^4−5x^3−x^2−6x+4

this is how to do this:


there are two sign changes which mean, there are two or 0(even number lower) positive solution.

to find negative soloution, invert the sign of the term with odd power

2x^4+5x^3 - x^2 + 6 x+4

which mean it has either 2 or 0 solution negative solution