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OpenStudy (anonymous):
StArAnGeL: 5x^4 y^2 (2x^5 y^6) / 20x^3 y^5
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OpenStudy (anonymous):
\[\frac{5x^4 y^2 (2x^5 y^6) }{ 20x^3 y^5 }\]
Can you try ?
OpenStudy (anonymous):
uh.....er....uh....
OpenStudy (anonymous):
Okay \[\huge \frac{5 \times 2 \times x^4y^2x^5y^6}{20 x^3y^5}\]
OpenStudy (anonymous):
Now ? :)
OpenStudy (anonymous):
Do the same way as we did the previous problem
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OpenStudy (anonymous):
LOL! Kay...one sec,plz...
OpenStudy (anonymous):
Note: \[\huge x^m \times x^n =x^{m+n}\]\[\huge x^m \div x^n = x^{m-n}\]
OpenStudy (anonymous):
Is it fraction 1/2 x^6/y^3 ??
OpenStudy (anonymous):
If you meant this one
You are absolutely right :)
\[\huge \frac{1}{2} x^6y^3 \]
OpenStudy (anonymous):
Why isnt it over y^3 though???
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OpenStudy (anonymous):
I get it.THANK YOU!!!!!!! You are my new favorite :) your better than my teacher! Your on often right? (Please say yes)
OpenStudy (anonymous):
I get it.THANK YOU!!!!!!! You are my new favorite :) your better than my teacher! Your on often right? (Please say yes)
OpenStudy (anonymous):
Okay lets consider y we have \[\huge \frac{y^2 \times y^6}{y^5} \] Which is equal to\[\huge \frac{y^{2+6}}{y^5}= \frac{y^8}{y^5}=y^{8-5}=y^3\]
OpenStudy (anonymous):
Glad to hear that :D i will try to help you whenever i am on
OpenStudy (anonymous):
!!! :D :D :D
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