8m-16 ÷ 3m-6 -20 40
I am not sure I understand you question - can you please clarify?
is this:\[(8m-16)\div(3m-6)\]with two choices for the answer: -20 or 40?
no the 20 should have a line above it but under the 8m-16 and the same with the 40 and 3m-16
ok, so question is:\[\frac{8m-16}{20}\div\frac{3m-6}{40}\]correct?
yes it wouldnt let me type it like that but thats correct
ok, do you the rule for dividing fractions? i.e. this rule:\[\frac{a}{b}\div\frac{p}{q}=\frac{a}{b}\times\frac{q}{p}\]
*do you know the rule...
yes
so we can make use of this to get:\[\frac{8m-16}{20}\div\frac{3m-6}{40}=\frac{8m-16}{20}\times\frac{40}{3m-6}\]
you can also factorise a bit to get:\[\frac{8m-16}{20}\times\frac{40}{3m-6}=\frac{8(m-2)}{20}\times\frac{40}{3(m-2)}\]
you now be able to cancel some things out. are you able to work it out yourself from here?
ok once i cancel out the m-2 i get lost
bec ause the 20 is negative
ok, let me show you the steps...
oh - so the equation I wrote was not correct?
im sorry i thought u put a -20
are you saying it should be:\[\frac{8(m-2)}{-20}\times\frac{40}{3(m-2)}\]
yes
ok , I'll try and illustrate the steps to you...
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