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OpenStudy (anonymous):
OpenStudy (anonymous):
y=mx+c
From the graph we can see that the y-intercept is -2
To find the gradient, pick two point and enter it into this equation
\[m=\frac{y_2-y_1}{x_2-x_1}\]
OpenStudy (anonymous):
so do i divide
OpenStudy (anonymous):
for the gradient or slope? yes
OpenStudy (anonymous):
which 2 points should i pick
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OpenStudy (anonymous):
it doesn't matter which they will all give you the same slope.
OpenStudy (anonymous):
is 3 correct
OpenStudy (anonymous):
Yes it is. So what is your equation?
OpenStudy (anonymous):
idk i'm lost
OpenStudy (anonymous):
Okay so you have worked out your slope which is 3 and we know the y-intercept (occurs at x=0) from looking at the graph and it was -2.
This means m=3 and c=-2.
The equation of a straight line is y=mx+c. All you have to do is place the values into the equation. What do you get?
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OpenStudy (anonymous):
4.5
OpenStudy (anonymous):
-4.5
OpenStudy (anonymous):
Ahh okay, y=mx+c, m=3 and c=-2.
The equation of the line is then y=3x-2. And that is the answer