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Mathematics 18 Online
OpenStudy (anonymous):

What is the equation of the line:

OpenStudy (anonymous):

OpenStudy (anonymous):

y=mx+c From the graph we can see that the y-intercept is -2 To find the gradient, pick two point and enter it into this equation \[m=\frac{y_2-y_1}{x_2-x_1}\]

OpenStudy (anonymous):

so do i divide

OpenStudy (anonymous):

for the gradient or slope? yes

OpenStudy (anonymous):

which 2 points should i pick

OpenStudy (anonymous):

it doesn't matter which they will all give you the same slope.

OpenStudy (anonymous):

is 3 correct

OpenStudy (anonymous):

Yes it is. So what is your equation?

OpenStudy (anonymous):

idk i'm lost

OpenStudy (anonymous):

Okay so you have worked out your slope which is 3 and we know the y-intercept (occurs at x=0) from looking at the graph and it was -2. This means m=3 and c=-2. The equation of a straight line is y=mx+c. All you have to do is place the values into the equation. What do you get?

OpenStudy (anonymous):

4.5

OpenStudy (anonymous):

-4.5

OpenStudy (anonymous):

Ahh okay, y=mx+c, m=3 and c=-2. The equation of the line is then y=3x-2. And that is the answer

OpenStudy (anonymous):

ty

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