Question

What is the third–degree polynomial function such that f(0) = –18 and whose zeros are 1, 2, and 3?

Answer 1

Ahh thank you!!!

Answer 2

wait, lol. I didn't see the f(0) = -18 part

Answer 3

oh. so what do i do im soooo confused!

Answer 4

you know it is
\[f(x)=a(x-1)(x-2)(x-3)\] and you also know the constant is 18 since
\[f(0)=18\] the only thing you don't know is "a"

Answer 5

\[a\times -1\times -2\times -3=-6a=18\] therefore
\[a=-3\]

Answer 6

and so your answer is
\[f(x)=-3(x-1)(x-2)(x-3)=-3 x^3+18 x^2-33 x+18\]

Answer 7

@luis unfortunately when you tack on -18 at the end of the product, the zeros are no longer 1,2 and 3

Answer 8

satellite is the master

Answer 9

of disaster!

Answer 10

lol i hate algebra!!!! its mean