Question

differentiate log(x(root(x+1))

Answer 1

\[\ln x \sqrt{x+1} =y\]

Answer 2

rewrite first as
\(y=\ln(x)+\frac{1}{2}\ln(x+1)\)
Therefore
\(y'=\frac{1}{x}+\frac{1}{2(x+1)}\)

Answer 3

\[\ln (x \sqrt{x+1}) =y\] ?

Answer 4

Can you restate your question please, I will show you a good way to deal with derivatives well at least that I use. Just split the equation into pieces and derive the pieces then place them all together

Answer 5

@BlingBlong is it the way watchmath has shown
thanks@ watchmath!