Question

If you have 400.0 mL of water at 25.00 °C and add 140.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Answer 1

\[(mass)(\Delta T)(C_s)=(C_s)(\Delta T)(mass)\]

Answer 2

\[(140.0g)(95.00-x)(4.184)=(4.184)(x-25.00)(400.0g)\]

Solve for x

Answer 3

55647.2-585.76x=x1673.6x-41840

97487.2=2259.36x

x=43.15

Answer 4

where did you get the 4.184?

Answer 5

it's the specific heat capcity for water.

Answer 6

ah thanks