Question

Landing with a speed of 75.6, and traveling due south, a jet comes to rest in 933.
Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

Answer 1

Ok, I got this problem wrong but I'm not sure why. I'll post my work.

Answer 2

*75.6m/s
*933m

Answer 3

t=933/75.6 => t=12.3 s
a=v/t => 75.6/12.3= 6.14m/s^2

Answer 4

The accelartion is negative

Answer 5

Yeah, I actually had -6.14 m/s^2 and it was wrong.

Answer 6

\[0^{2}=75.6^{2}+2a933\]

Answer 7

Can you explain that formula?

Answer 8

\[v ^{2}=v _{0}^{2}+2ad\]