1+2+3+...+49+50=
s=n(n+1)/2
50.51/2=25.51
\[\sum_{k=1}^{n}k=\frac{n(n+1)}{2} \implies \sum_{k=1}^{50}=\frac{50(51)}{2}=1275\]
don't you think it's much much easier to be solved
ya.........
....No? That is the easiest way to solve it? lol
We can do this by two methods: 1.The Formula Method(malevolence has already done it) 2.The Gaussian Pairing Tool : 50+1=51,49+2=51......therefore 1+2+.......+49+50 = 51*50/2 = 1275
You could just add them up but you'll get the same number...
lol
i mean just solve it not writing the formula
dnt complicate it aron
The "Gaussian Pairing Tool" is the formula...
Its just generalized to n things being added...I just wanted to show you where it came from...Type it into wolfram if you just want the number.
we can also use programing :D
lol
no dont....
w8 lemme make it :D
can u teach me about addition of harmonic mean
hey let's pass it . this question doesn't worth to discuss on
tanu did that in high school bt may b i will revise on tuesday and then teach u ok
it's for elementry school
malevolence ur good
a program that calculates sum of arithematic series with difference =1
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