Question

how would I solve

log(4x+14)^841=2

Answer 1

so first we need to know what is the base of log(4x+14)

Answer 2

841 log ( 4x + 14 ) = 2
log ( 4x + 14) = 2/841
4x + 14 = e^(2/841)
4x = e^(2/841) - 14
x = [ e^(2/841) - 14]/4

Answer 3

4x+14 is the base

Answer 4

scrap my answer then

Answer 5

but than the base how can being on exponent ?

Answer 6

841 log ( 4x + 14 ) = 2
log ( 4x + 14) = 2/841
4x + 14 = 10^(2/841) (correction)
4x = 10^(2/841) - 14 (correction)
x = [ 10^(2/841) - 14]/4 (correction)

Answer 7

Busterkitten i think you need rewrite please your exersice correct

Answer 8

To cancel log we need to raise to the power of 10 and not e, if it was ln then we would have used e.

Answer 9

log(4x+14) 841=2

Answer 10

- so than you know the logarithm property how we can changeing the base of one logarithm ?