Question

equation of the circle shown is...

Answer 1

indeterminate

Answer 2

ishaan nice picture

Answer 3

thanks! :-D

Answer 4

it's an egg! :P

Answer 5

x^2 + (y-a)^2 = a^2
x^2 + y^2 - 2ya = 0

a is the radius.

Answer 6

lol

Answer 7

where radius=a.
a) y^2+(x-a)^2=a^2
b)x^2=y^2+a^2
c)(x+y)^2=a^2
d)x^2+(y-a)^2=a^2
e)none of the above

i was gonna say none of the above but it's d isn't it?

Answer 8

i think you can get it now

Answer 9

ok thx

Answer 10

is x^2+y^2=a^2 always at the origin?

Answer 11

yeah

Answer 12

ok thx

Answer 13

d does look the most promising

Answer 14

(x-0)^2 + (y-0)^2 = a^2; is centered at (0,0)

Answer 15

I second amistre64

Answer 16

with any luck i wont be voted off the island :)

Answer 17

Youe answer should be \( d)x^2+(y-a)^2=a^2\)

Answer 18

wow, that took a while