Question

Expand the Expression x>0 , y>0 , z>0

log (x^2/yz^4)

Answer 1

log a/b = loga - logb

log ab = loga + logb

Answer 2

log n^r = r logn

Answer 3

him can you elaborate more please

Answer 4

not really, those are the basic rules for log operations. I can complicate them, but I doubt I can make them any easier ...

Answer 5

can you giveme an example and work it out

Answer 6

ok, but its just gonna be the same thing but with numbers in there

Answer 7

log (1/2) = log(1)-log(2)

log(4*3) = log(4)+log(3)

log(6^3) = 3 log(6)

Answer 8

youll need all these operations to expand the one youve got

Answer 9

so the final answer would be 3log(6)?

Answer 10

loga (x^2/yz^4)--what do i do with a

Answer 11

"a" stays the same unless your asked to change of base it

Answer 12

log (x^2/yz^4)

do you see the division sign? the fraction bar?

split this into its subtraction parts

Answer 13

yesI understand it now! thanks

Answer 14

log (x^2/yz^4) = log (x^2) - log (yz^4)

where you see the multiplication, split it into its addition parts

log (x^2/yz^4) = log (x^2) - log (y)+ log(z^4)

and where you see exponents, turn it into its like parts

Answer 15

log (x^2/yz^4) = 2log (x) - log (y)+ 4log(z)

Answer 16

the base "a" doesnt change thruout it unless directed otherswise

Answer 17

i might have a typo in there :)

Answer 18

log (x^2/yz^4) = log (x^2) - (log (y)+ log(z^4))

is better since the hole of it is subtracted

log (x^2/yz^4) = log (x^2) - log (y) - log(z^4)

and then its the same from there