Question

STATISTICS

Answer 1

1. A physician wanted to estimate the mean length of time that a patient had to wait to see him after arriving at the office. A random sample of 36 patients showed a mean waiting time of 23.4 minutes and a standard deviation of 7.2 minutes. Find a 96% confidence interval for .

Answer 2

sd/sqrt(n) sounds familiar

Answer 3

\[z=\frac{x-mean}{sd/\sqrt{n}}\]

Answer 4

where z is the value at Za = .02 maybe?

Answer 5

i know im missing something :/

Answer 6

we want the interval of Lx to Rx right?

Answer 7

z = 2.06 if i see the table right

Answer 8

\[z=\frac{x-mean}{sd/\sqrt{n}}\]
\[z(sd/\sqrt{n})={x-mean}\]
\[z(sd/\sqrt{n})+mean={x}\]
\[2.06(7.2/\sqrt{36})+23.4={x}\text{ to the right}\]
\[-2.06(7.2/\sqrt{36})+23.4={x}\text{ to the left}\]

Answer 9

with any luck that is :) im sure im forgetting something important tho