A square is inscribed inside a circle. The square's vertices have coordinates R(0, 4), S(6, 2), T(4, -4), and U(-2, -2). Find the equation of the circle.
(x - )^2 + y2 =

Question

A square is inscribed inside a circle. The square's vertices have coordinates R(0, 4), S(6, 2), T(4, -4), and U(-2, -2). Find the equation of the circle.
(x -      )^2 + y2 =

anonymous · Answer

Center of circle is center of square and radius is (side length)/sqrt(2)

dumbcow · Answer

|dw:1327304370411:dw|
center = midpoint of RT
diameter = length of RT

center = (2,0)
diameter = sqrt(4^2 + 8^2) = sqrt(80) = 4sqrt(5)
--> radius = 2sqrt(5)

circle: (x-2)^2 + y^2 = 20