Question

[(e^x)-(1)-(x)]/ (x^2) as lim x --> 0

Answer 1

Again apply L' Hospital's Rule to get 1/2 as the limit.

Answer 2

how? =(

Answer 3

expand e^x and see it fall all in place
ans is 1/2

Answer 4

cant get the answer but i believe you

Answer 5

lol

Answer 6

how exactly did u expand e to x

Answer 7

The given limit is in its indeterminate form thus we differentiate the numerator and denominator to get 1/2[(e^x - 1)/x] now the limit of [e^x - 1/]x is nothing but 1.

Answer 8

e^x is expanded by using the Taylor Series.

Answer 9

That is euler series not Taylor

Answer 10

i didnt know you can just differentiate the numerator and the denominator while the numerator was being subtracted from e^x - 1

Answer 11

It is actually Maclaurin series which is a special case of Taylor Series.

Answer 12

If you want you can actually prove it using cauchy mean valuue theorem

Answer 13

can someone quickly show me how you get the answer to my other problem under this? thank you

Answer 14

WHere is the other problem