when do i use sin, cos and tan in inverse form?
an example might be that you are told the sin of an angle is 0.5 and asked to find the angle. then you would use the inverse sin function.
does that help?
so when looking for the sides of a triangle?
when looking for sides, you usually use the sin/cos/tan functions. the inverses are usually used to find the angles.
so you might be given an angle and one side, and asked to find another side - that involves using sin/cos/tan. on the other hand, you might be given 2 sides and asked to find the angle - that involves using the inverse functions.
ohh ok... |dw:1327355865365:dw| how would i do this?
\[\cos(60)=\frac{5}{x}\]therefore:\[x=\frac{5}{\cos(60)}\]
cosine is a/h?
yes
you can use the mneumonic SohCahToa to remember them. Soh ===> sin = o/h Cah ===> cos = a/h Toa ===> tan = o/a
you pronounce it as "SAW CAH TOE AH"
when i have that e
equation set up.. how do you solve for the x tho?
just work out the fraction - 5 divided by cosine of 60 degrees. I'm not sure where you are stuck?
sry.. i thought it was 5/x tho?
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