Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Solve a definite integral using Simpson's Rule

OpenStudy (anonymous):

\[\int\limits_{0}^{6}x ^{2}dx\]

OpenStudy (anonymous):

Using Simp(2)

OpenStudy (anonymous):

This is just chug and plug I believe.

OpenStudy (zarkon):

it will be the same as the actual answer

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

Yes Zarkon is right, but actually simpson formula would be tedious in this case.

OpenStudy (zarkon):

simpsons rule is exact for a quadratic function

OpenStudy (anonymous):

lol fool i need to use it though

OpenStudy (anonymous):

can you tell me the formula of simpson's rule?

OpenStudy (anonymous):

6/6[ f(0) + 4f( .5 ) + 2f(1) + 4f(1.5) + 2f( 2) + 4f( 2.5) + 2f( 3) + 4f ( 3.5) + 2f( 4) + 4f (4.5 ) +2 f( 5) +4 f( 5.5 ) + f( 6) ]

OpenStudy (zarkon):

http://en.wikipedia.org/wiki/Simpson%27s_rule

OpenStudy (anonymous):

Btw If I remember correctly there is another constraints that should be involved which is number of decimal places.

OpenStudy (anonymous):

oh Thanks Zarkon :D

OpenStudy (anonymous):

Well we learnt the formula (2M+T)/3

OpenStudy (anonymous):

I guess this is pretty tedious

OpenStudy (anonymous):

try computing the error estimate :)

OpenStudy (anonymous):

Yes it is but this formula useful for somewhat complicated integrals.

OpenStudy (anonymous):

yea, som thing cannot be integrated( easily) this is sometime a way to approximate a solution.

OpenStudy (anonymous):

Thanks zarkon <Roachie and fool

OpenStudy (anonymous):

just try to have fun with it!

OpenStudy (anonymous):

LOL Trying but mt brain is fried lol

OpenStudy (anonymous):

you can find the definite integral?

OpenStudy (anonymous):

lol I am in the midst of figuring it out

OpenStudy (anonymous):

ok then do it with Simp and see!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!