Question

Find two Square roots for 4i. Leave in standard/rectangular form.
Help would be much appreciated! :)

Answer 1

\[\sqrt4 = \pm2\]

Answer 2

thanks, but that's for 4, not 4i :)

Answer 3

\[4i= 4 e ^{i \Pi/2}\]

Answer 4

so, square root of 4i is \[\pm2 e ^{i \Pi/4}=\pm2(\cos \Pi/4 + i \sin \Pi/4)\]

Answer 5

simplify it, u will get:
\[\pm \sqrt{2} (1+i)\]

Answer 6

Thank you!

Answer 7

welcome :)