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OpenStudy (mertsj):
\[\frac{1}{9}=3^{-2}\]
OpenStudy (mertsj):
\[27^{x-1}=(3^{3})^{x-1}\]
OpenStudy (mertsj):
\[(3^{3})^{x-1}=3^{3x-3}\]
OpenStudy (mertsj):
So:\[3^{-2}=3^{3x-3}\]
OpenStudy (mertsj):
And -2=3x-3
1=3x
1/3=x
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OpenStudy (anonymous):
Can you please help me with one more??? PLEASE!! begging you.
OpenStudy (mertsj):
Post it.
OpenStudy (anonymous):
properties of logarithms: 3^x=5^x+2
OpenStudy (anonymous):
3^x=5^(x+2)
OpenStudy (mertsj):
\[x \log_{10}3=(x+2)\log_{10}5 \]
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OpenStudy (anonymous):
How did you get that?
OpenStudy (mertsj):
Find the log of 3 and the log of 5 using your calculator and solve the equation.
OpenStudy (mertsj):
\[a ^{n}=n \log_{10}a \]
OpenStudy (anonymous):
how did you know what the variables were?
OpenStudy (mertsj):
That is the property of law of logs. Perhaps your book uses different variables. What the variables are doesn't matter. Did you book say:
\[m ^{n}=n \log_{10}m \]
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OpenStudy (anonymous):
oh eyes!
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
So use that property on 3^x
OpenStudy (mertsj):
Would you not get xlog3?
OpenStudy (anonymous):
I think my answer is wrong :/
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OpenStudy (mertsj):
What did you get?
OpenStudy (anonymous):
4.52
OpenStudy (mertsj):
Hang on.
OpenStudy (mertsj):
xlog3=.477x and (x+2)log 5 = .699x+1.40
OpenStudy (mertsj):
do you agree with that/
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OpenStudy (anonymous):
Yes!
OpenStudy (mertsj):
Subtract .699x from both sides.
OpenStudy (mertsj):
-.222x=1.40
OpenStudy (anonymous):
Oh so the final answer is 1.40?
OpenStudy (mertsj):
Now divide both sides by -.222
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OpenStudy (anonymous):
Oh so -6.31?
OpenStudy (mertsj):
yes.
OpenStudy (anonymous):
THANK YOU SO MUCH! seriously, you are my life-saver. Now I have one more, I don't want to make you have to show me but could I just ask you a question about it?