if each interior angle of a regular polygon measures 144 degrees, how many sides does the polygon have?
Please show steps on how to solve.
obtuse angles but idont know about a polygon with obtuse angles
Ok. What's the sum of angles of a triangle? 180 degrees. A triangle is a polygon with 3 sides. What's the sum of the angles of a square? A square is a polygon with 4 sides. What's the answer here?
the answer is supposed to be 10 sides how do you solve that?
decagon?
We'll get there ... follow me in logic first
ok
What's the sum of angles of a square?
180 (4-2) = 360
360 ofcourse.as all angles are 90
the polygon in question has 10 sides
^ why?
Right ... so you've got the formula for an n-sided polygon. It has a sum of angles \[ 180(n-2) \] and that's because you can make a polygon out of triangles. Stick two triangles together and you have a square, hence the sum of their angles is 180 + 180. Take a square add a triangle and you have a pentagon.|dw:1327439866826:dw|
i know how to do that, how do you solve when you dont know the number of sides?
Now, if an n-sided polygon has a sum of angles 180(n-2), what's the size of the angles if each of them is the same? Well, there are n angles, hence one angle has the size of \[ \frac{180(n-2)}{n} \]
For your problem, set that equal to 144 and solve for n.
the general rule is Each Angle (of a Regular Polygon) = (n-2) × 180° / n so 144=(n-2)x180/n 144n=(n-2)x180 144n=180n-360 144n-180n=-360 36n=360 n=10
so, James J, i do 180 (n-2) / n = 144 144-180+2= n/n?
NOPE THATS NOT RIGHT ^
i dont understnad..
Safiah has written this out for you. But to start it off again \[ \frac{180(n-2)}{n} = 144 \] hence \[ 180(n-2) = 144n \] Can you do it now?
OH WOW I GET IT!
sooo 180( n-2) = 144n wiat no, what do i do now?
...hence \[ 180n - 360 = 144n \] Now?
expand the brackets hellobudy
nope.. now what?
Subtract 144n from both sides... \[ 180n - 144n - 360 = 0 \] i.e. \[ 36n - 360 = 0 \] Now can you finish it?
-360 = -36 and then you divide 360 by 36 and you get ten
right, \[ 36n = 360 \] hence \[ n = \frac{360}{36} = 10 \]
k i think i get it..
thank you!
Do yourself a favor. Take a blank piece of paper. Write out the solution again. When you can do that without looking at anything --such as this web or another version of the solution--then you know you understand the solution.
ok! can you give me another example so i can practice? use a different degrees?
ok ill try with 100 degrees
No, that won't work. One sec.
try 108 degrees
ALRIGHT :)
5 sides?
yes
:D
last one, 162 degrees
20 :)
what about for 180 degrees?
huh?
That would correspond to a regular polygon with an infinite number of sides. What does that look like?
idk waht your asking
It would look like a circle.
As you add more and more sides to a regular polygon, it looks more and more like a circle. In the limit, as the number of sides goes to infinity, it would become a circle. http://www.ck12.org/ck12/images?id=301055
thanks :)
g2g
Here's an even better picture of this idea:
thanks!
Great job JamesJ - and way to hang in there hellobuddy!
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